The spring was compressed by 4.2 cm. What was the elastic force if the spring rate was 4000 N / m?
| January 13, 2021 | education
Initial data: Δx (amount of compression of the spring) = 4.2 cm (4.2 * 10-2 m); k (compressive spring stiffness) = 4000 N / m.
The force of elasticity that arose in the spring is determined by the formula: Fel. = | k * Δх |.
Calculation: Fcont. = 4000 * 4.2 * 10-2 = 168 N.
Answer: When the spring was compressed, an elastic force of 168 N.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
