The steam turbine efficiency is 35%. What is the temperature of the refrigerator if the heater temperature is 427C.

These tasks: η (efficiency of the considered steam turbine) = 35% (0.35); Тн (heater temperature) = 427 ºС (absolute temperature Тн = 700 К).

The desired temperature of the refrigerator can be expressed from the formula: η = 1 – Тх / Тн, whence Тх / Тн = 1 – η and Тх = (1 – η) * Тн.

Let’s perform the calculation: Тх = (1 – 0.35) * 700 = 455 К (on the Celsius scale Тх = 182 ºС).

Answer: The refrigerator has a temperature of 455 K (182 º C).



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