The steamer took 60 tons of oil on the voyage. How much charcoal would be fashionable to replace this amount of oil?

Initial data: m1 (mass of oil that the steamer took on the voyage) = 60 tons (60 * 10 ^ 3 kg).

Reference values: q1 (specific heat of combustion of oil) = 4.4 * 10 ^ 7 J / kg; q2 (specific heat of combustion of charcoal) = 3.4 * 10 ^ 7 J / kg.

The amount of charcoal that can replace 60 tons of oil is determined from the equality: q1 * m1 = Q = q2 * m2, whence m2 = q1 * m1 / q2.

Calculation: m2 = 4.4 * 10 ^ 7 * 60 * 10 ^ 3 / (3.4 * 10 ^ 7) = 77 647 kg.

Answer: The steamer will need to take 77 647 kg of charcoal.