The steel ball flies at a speed of 40 m / s and hits an obstacle. How much does the ball heat up on impact?

Initial data: V (flight speed of the steel ball) = 40 m / s.

Constants: C (specific heat capacity of steel) = 500 J / (kg * K).

We will assume that during the impact, all the kinetic energy of the steel ball went to its heating.

Q1 = Q2; Ek = Q2; m * V ^ 2/2 = C * m * Δt; 0.5V ^ 2 = C * Δt.

Δt = 0.5V ^ 2 / C.

Let’s perform the calculation:

Δt = 0.5 * 40 ^ 2/500 = 1.6 ºС.

Answer: The steel ball will heat up by 1.6 ºС upon impact.