# The steel ball moves at a speed of 10 m / s and hits the wall.

The steel ball moves at a speed of 10 m / s and hits the wall. Find the change in the temperature of the ball if 40% of the mechanical energy is used for heating.

To find the change in temperature of the steel ball taken, we apply the formula: η = Q / Ek = Cc * m * Δt / (m * V ^ 2/2), from where we express: Δt = η * V ^ 2 / (2 * Cc).

Constants and variables: η – percentage of mechanical energy losses (η = 40% = 0.4); V is the speed of the steel ball before hitting the wall (V = 10 m / s); Сс – specific heat capacity of steel (Сс = 500 J / (kg * K)).

Calculation: Δt = η * V ^ 2 / (2 * Cc) = 0.4 * 10 ^ 2 / (2 * 500) = 0.04 ºС.

Answer: The temperature of the taken steel ball after the impact increased by 0.04 ºС.

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