The steel ball was dropped without initial velocity from a certain height and reached the earth’s

The steel ball was dropped without initial velocity from a certain height and reached the earth’s surface at a speed of 29.4 m / s. Find the fall time. Disregard air resistance.

To find the required duration of the fall of the steel ball, we use the formula (we take into account that the ball fell without initial velocity): V = V0 + a * t = 0 + g * t, whence we express: t = V / g.

Constants and variables: V – speed of the steel ball at the surface (V = 29.4 m / s); g – acceleration due to gravity (g ≈ 9.8 m / s2).

Calculation: t = V / g = 29.4 / 9.8 = 3 s.

Answer: The duration of the fall of the steel ball is 3 seconds.