The steel part has a mass of 7.8 kg, determine the volume of the part, the density of steel is 7800 kg / m3
| February 7, 2021 | education
Given:
m = 7.8 kg is the mass of the steel part;
ro = 7800 kg / m ^ 3 – steel density.
It is required to determine V (m ^ 3) – the volume of the steel part.
V = m / ro = 7.8 / 7800 = 0.001 m ^ 3.
Answer: The volume of the steel part is 0.001 m ^ 3.
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