The steel part of the machine has a mass of 0.78 kg. The density of the steel is 7.8 g / s. Its volume?
| August 30, 2021 | education
Initial data: m (weight of the steel part of the machine) = 0.78 kg.
Reference values: according to the condition ρс (steel density) = 7.8 g / cm3 = 7800 kg / m3.
The volume of the steel part of the machine will be equal to the ratio of its mass and density of steel: V = m / ρс.
Calculation: V = 0.78 / 7800 = 0.0001 m3 = 100 cm3.
Answer: The volume of the steel part of the machine is 100 cm3.
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