The steel part, the temperature of which has decreased from 320 C to 20 C, gives the environment 900 kJ.

The steel part, the temperature of which has decreased from 320 C to 20 C, gives the environment 900 kJ. determine the mass of the steel part.

Given:
t2 = 320 C
t1 = 20 C
c = 500 J / kg * C
Q = 900 kJ = 900000 J
Find: m -?
Decision:
Q = c * m * (t2-t1)
m = Q / c * (t2-t1)
m = 900000/150000 = 6 (kg)
Answer: 6 kg.



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