The stiffness of the steel wire is 10,000 N / m. how much the cable will lengthen if a load of 20 kg is suspended from it.

To find out the elongation of the steel wire taken, consider the equality: Fel (elastic force) = Ft (gravity) and k * Δx = mg * g, from where we express: Δx = mg * g / k.

Const: g – acceleration due to gravity (g ≈ 10 m / s2).

Data: mg – weight of the suspended load (mg = 20 kg); k is the stiffness of the steel wire taken (k = 10000 N / m).

Let’s make the calculation: Δx = mg * g / k = 20 * 10/10000 = 0.02 m or 20 mm.

Answer: The elongation of the steel wire taken is 20 mm.