The stone falls freely without initial velocity from a height of 5 m. What is the velocity

The stone falls freely without initial velocity from a height of 5 m. What is the velocity of the stone at the moment of contact with the Earth, if all the work of the force of gravity went to increase its kinetic energy?

h = 5 m.
g = 9.8 m / s ^ 2.
V0 = 0 m / s.
V -?
The total energy of the stone E consists of the sum of its potential and kinetic energy E = En + Ek.
En = m * g * h, Ek = m * V ^ 2/2.
At the moment of the beginning of the movement, E consists only of potential energy, since the initial speed is 0.
E = m * g * h.
At the moment of contact with the Earth, the altitude is 0, the total energy consists only of kinetic energy
E = m * V ^ 2/2.
m * g * h = m * V ^ 2/2.
V = √2 * g * h.
V = √2 * 9.8 m / s ^ 2 * 5 m = 9.9 m / s.
Answer: the speed of the stone at the moment it touches the Earth is V = 9.9 m / s.