The stone is thrown at an angle of 20 degrees to the horizon with an initial speed of 13 m / s

| February 7, 2021 | education

The stone is thrown at an angle of 20 degrees to the horizon with an initial speed of 13 m / s. Determine the maximum height of the stone to rise?

∠α = 20 °.

V0 = 13 m / s.

g = 9.8 m / s2.

hmax-?

The motion of a stone can be divided into two types: horizontally, it moves uniformly at a speed V0х, vertically uniformly accelerated with an acceleration of gravity g and an initial speed V0у.

V0х = V0 * cosα.

V0у = V0 * sinα.

The height of the stone lifting h is expressed by the formula: h = (V0у ^ 2 – Vу ^ 2) / 2 * g, where V0у, Vу are the initial and final vertical component of the stone speed.

At the maximum height hmax, the stone stops Vу = 0 m / s, the formula will take the form: hmax = V0у ^ 2/2 * g = (V0 * sinα) ^ 2/2 * g.

hmax = (13 m / s * sin20 °) ^ 2/2 * 9.8 m / s2 = 1 m.

Answer: the maximum height of the stone lifting is hmax = 1 m.



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