The stone is thrown vertically downward at a speed of 10 m / s. What is the speed of the stone

The stone is thrown vertically downward at a speed of 10 m / s. What is the speed of the stone at the moment of impact on the ground, if the throw is made from a height of 20m.

You can express the speed of a stone at the moment it hits the ground from the following formula:

S = (V ^ 2 – V0 ^ 2) / 2a, where S is the movement of the stone, the height of the fall (S = h = 20 m), V is the final velocity of the stone, V0 is the initial velocity of the stone (V0 = 10 m / s) , a is the acceleration of the stone (a = g = 10 m / s2).

2g * S = V ^ 2 – V0 ^ 2.

V ^ 2 = 2g * S + V0 ^ 2.

V = √ (2g * S + V0 ^ 2) = √ (2 * 10 * 20 + 10 ^ 2) = √ (400 + 100) = √ 500 = 22.36 m / s2.

Answer: The speed of the stone at the moment of impact on the ground was equal to 22.36 m / s2.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.