The stone is thrown vertically upward at a speed of 5.25 m / s. What is the speed of a stone at a height of 1m?

univerkov | December 29, 2020 | education

Let us write the law of conservation of energy for this case:
Ek1 = Ep + Ek2
mV ^ 2/2 = mgh + mU ^ 2/2
V ^ 2/2 = gh + U ^ 2/2
V ^ 2 = 2gh + U ^ 2
U = sqrt (V ^ 2-2gh) = sqrt (7.5625) = 2.75m / s

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