The stone is thrown vertically upward with an initial velocity v = 30m / s to what maximum height will the stone rise

The stone is thrown vertically upward with an initial velocity v = 30m / s to what maximum height will the stone rise and what is the time of its rise to this height?

it is possible through the law of conservation of total energy (mV ^ 2) / 2 = mgh h = V ^ 2 / 2g; h = 30 * 2/2 x 10 = 45m and find the time through this formula => U = U0-gt => U0 = gt => t = Uo / g => t = 3c
Answer: h = 45m, t = 3 s.