The stone thrown upwards reached the highest point of the trajectory three seconds after the throw.

The stone thrown upwards reached the highest point of the trajectory three seconds after the throw. How fast was the stone thrown?

To find the value of the required speed of throwing the specified stone, we apply the formula: Vн = a * t = g * t.

Data: g – acceleration due to gravity (g = 9.81 m / s2); t – the duration of the movement of the specified stone to the highest point (t = 3 s).

Let’s perform the calculation: Vн = g * t = 9.81 * 3 = 29.43 m / s.

Answer: The speed of throwing the indicated stone was equal to 29.43 m / s.



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