The stone was thrown from the cliff into the abyss vertically downward with an initial speed of 2 m / s.

The stone was thrown from the cliff into the abyss vertically downward with an initial speed of 2 m / s. What, respectively, are the speed module of the stone and the distance traveled by it in 0.5 s of flight?

The fall of the stone will obey the law of rectilinear uniformly accelerated motion, the acceleration of gravity is 9.8 m / s2. Let’s find the speed and movement of the stone:

v (t) = v0 + g * t = 2 + 9.8 * 0.5 = 6.9 m / s;

S = v0 * t + gt ^ 2/2 = 2 * 0.5 + 9.8 * 2 ^ 2/2 = 20.6 m.

Answer: v = 6.9 m / s; S = 20.6 m.