The stone was thrown upwards from a height of 2 m with an initial speed of 5 m / s. What is the maximum height it will climb?
| December 29, 2020 | education
This case is the movement of a body thrown vertically upward with an initial velocity. Body movement vertically up = uniformly accelerated movement.
Then:
h = V ^ 2 / 2g = 25/20 = 1.25m.
since the body originally had a height of 2m, then H = h + 2 = 3.25m
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