The stone was thrown vertically downward with an initial speed of 2 m / s. The speed of the

The stone was thrown vertically downward with an initial speed of 2 m / s. The speed of the stone after 0.5 s of flight is equal to?

Problem data: V0 (initial speed with which the stone was thrown vertically downward) = 2 m / s; t (duration of the stone falling) = 0.5 s.

Reference values: a (acceleration of a stone) = g (acceleration of gravity) ≈ 10 m / s2.

The speed of the stone in half a second of flight is determined by the formula: V = V0 + a * t = V0 + g * t.

Calculation: V = 2 + 10 * 0.5 = 2 + 5 = 7 m / s.

Answer: After half a second of flight, the speed of the stone will be 7 m / s.



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