The stone was thrown vertically upward with a night speed of 30 m / s. what is the maximum height of the stone?

V0 = 30 m / s.

g = 10 m / s2.

V = 0 m / s.

h -?

Since only gravity acts on the stone, therefore it moves uniformly with the acceleration of gravity g.

The height of the stone is determined by the formula: h = (V0 ^ 2 – V ^ 2) / 2 * g, where V0, V are the initial and final speed of the stone.

Since at the maximum height h the stone stops V = 0 m / s, the formula will take the form: h = V0 ^ 2/2 * g.

h = (30 m / s) ^ 2/2 * 10 m / s2 = 45 m.

Answer: the stone will rise to a maximum height of h = 45 m.