The straight line is given by the equation 2x + 3y + 25 = 0. Does the point K (-4; -7) belong to this straight line?

2x + 3y + 25 = 0 ⇔ x = (-3y – 25) / 2.

For x = -4, the equality takes the form -4 = (-3y – 25) / 2. Let’s solve the resulting equation.

-4 = (-3y – 25) / 2. | * 2

-8 = -3y – 25. | * (-one)

8 = 3y + 25.

3y = 8 – 25.

3y = -17.

y = -17 / 3.

-17/3 ≠ -7 ⇒ point K does not belong to the specified schedule.

Answer: K does not belong to the straight line.



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