# The straight line y = kx + b passes through point A (2.5; 1). The slope (k) of this straight line is -0.4.

**The straight line y = kx + b passes through point A (2.5; 1). The slope (k) of this straight line is -0.4. Write down the equation of this line and find the coordinates of the point at which it intersects the x-axis**

Since, according to the condition of the problem, the slope (k) of this straight line is -0.4, the equation that sets this straight line can be written in the form y = -0.4x + b.

Since this straight line passes through point A with coordinates (2.5; 1), the following relation must be satisfied:

1 = -0.4 * 2.5 + b.

Solving the resulting equation, we find the free term b:

1 = -1 + b;

b = 1 + 1 = 2.

Therefore, the equation of this line is y = -0.4x + 2.

Find the coordinates of the point at which this line intersects the OX axis:

0 = -0.4x + 2;

0.4x = 2;

x = 2 / 0.4 = 5.

Answer: the equation of the straight line y = -0.4x + 2, this straight line intersects the OX axis at the point (5; 0).