The strength of the current in the electric lamp of the searchlight is 2 A. How high is the voltage

The strength of the current in the electric lamp of the searchlight is 2 A. How high is the voltage supplied to the searchlight, if it consumes 45.6 kJ for 1 minute?

Data: I (current in the lamp of the searchlight) = 2 A; Q (energy consumed by the searchlight) = 45.6 kJ = 45.6 * 10 ^ 3 J; t (running time) = 1 min = 60 s.

Voltage supplied to the specified spotlight: U = Q / (I * t) = 45.6 * 10 ^ 3 / (2 * 60) = 380 V.

Answer: A voltage of 380 V is supplied to the indicated floodlight.



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