The strength of the current in the hair of the light bulb is 0.8 A. The resistance of the hair in the heated

The strength of the current in the hair of the light bulb is 0.8 A. The resistance of the hair in the heated state is 275 ohms. Find the voltage at which the light is on.

Given:

I = 0.8 Ampere – current in a hair of an electric bulb;

R = 275 – resistance of a hair of an electric bulb in a heated state.

It is required to determine U (Volt) – the voltage at which the light is on.

To determine the voltage, you must use the following formula (Ohm’s law for a section of the circuit):

I = U / R, from here we find that:

U = I * R;

U = 0.8 * 275 = 220 Volts.

Answer: the light bulb burns at a voltage of 220 volts.