The student was given the task of obtaining aluminum hydroxide with an amount of 0.1 mol of a substance

The student was given the task of obtaining aluminum hydroxide with an amount of 0.1 mol of a substance. He poured solutions containing 0.1 mol of aluminum chloride and 0.4 mol of sodium hydroxide. Was the student able to complete the task?

Given:
n (AlCl3) = 0.1 mol
n (NaOH) = 0.4 mol

To find:
Al (OH) 3 -?

Solution:
1) AlCl3 + 3NaOH => Al (OH) 3 ↓ + 3HCl;
2) n (Al (OH) 3) = n (AlCl3) = 0.1 mol;
3) n react. (NaOH) = n (AlCl3) * 3 = 0.1 * 3 = 0.3 mol;
4) n rest. (NaOH) = n (NaOH) – n re. (NaOH) = 0.4-0.3 = 0.1 mol;
5) Al (OH) 3 + NaOH => Na [Al (OH) 4];
Ultimately, the student will receive a complex salt (sodium tetrahydroxoaluminate), since aluminum hydroxide has amphoteric properties.

Answer: The student did not complete the task.