The submarine sank into the sea to a depth of 50 m. What is the pressure on the surface of the boat at this depth?

Seawater pressure on a submarine:

Р1 = ρ * g * h, where ρ is the density of seawater (for salt water ρ = 1030 kg / m3), g is the gravitational acceleration (const, g = 10 m / s2), h is the submersion depth of the submarine (h = 50 m).

Let’s make a calculation:

Р1 = ρ * g * h = 1030 * 10 * 50 = 515000 Pa = 515 kPa.

Atmospheric pressure on the submarine: P2 = 101.3 kPa.

Total pressure on the submarine: P = P1 + P2 = 515 + 101.3 = 616.3 kPa.

Answer: The pressure on the surface of the boat is 616.3 kPa.