The substitution reaction between copper (II) oxide and hydrogen gave 8 g of copper.
| December 3, 2020 | education
The substitution reaction between copper (II) oxide and hydrogen gave 8 g of copper. What is the mass of the copper (II) oxide that has reacted.
Given:
m (Cu) = 8 g
Find: m (CuO)
Decision:
CuO + H2 = Cu + H2O
Molar mass М (CuO) = 64 + 16 = 80 g / mol
Molar mass (Cu) = 64 g / mol
We take the mass of CuO as X
Then, through the proportion, we find
X / 80 = 8/64
X = 8 * 80/64
X = 10 g
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