The sulfur dioxide was dissolved in water and the solution was neutralized by adding sodium hydroxide.

| September 24, 2021 | education

The sulfur dioxide was dissolved in water and the solution was neutralized by adding sodium hydroxide. Add hydrogen peroxide to the resulting solution and after the end of the reaction sulfuric acid

1) Sulfur dioxide was dissolved in water.
SO2 + H2O = H2SO3;
When sulphurous gas interacts with water, the result is sulphurous acid.

2) Then, the solution was neutralized by adding sodium hydroxide.
H2SO3 + 2NaOH = Na2SO3 + H2O;
When sulphurous acid interacts, a sodium sulfite salt is formed.

3) Then added hydrogen peroxide.
NaSO3 + H2O2 = Na2SO4 + H2O;
As a result of the interaction of sodium sulfite and hydrogen peroxide, sodium sulfate and water are formed.

4) Then added sulfuric acid.
Na2SO4 + H2SO4 = 2NaHSO4;
When sodium sulfate and sulfuric acid interact, sodium hydrogen sulfate is formed.



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