The sulfur mineral contains pyrite FeS2 (mass fraction 80%) and other impurities, which do not contain

The sulfur mineral contains pyrite FeS2 (mass fraction 80%) and other impurities, which do not contain sulfur. Calculate the mass fraction of sulfur in the mineral.

1. Suppose m (mineral) = 100g, then:

m (FeS2) = 0.8 * 100 = 80g.

M (FeS2) = 120g / mol.

2. The amount of substance is found by the formula:

n = m / M

Substitute the values into the formula:

n (FeS2) = 80/120 = 0.667 mol.

3. Find the mass of sulfur:

m (S) = 2 * 0.667 * 32 = 42.688g.

4. Find the mass fraction of sulfur:

ω (S) = 42.688 / 100 * 100% = 42.7%.

Answer: ω (S) = 42.7%.