The sum of all sides of the rectangle ABCD 40 in. The length of the rectangle is 12 cm find the width of the rectangle.

1. If the sum of all sides is 40 dm, then the perimeter is 40 dm, which is 400 cm.
2. Calculate the width of the rectangle, subtracting its length from its semi-perimeter, we get:
400/2 – 12 = 200 – 12 = 188 cm.
Answer: The width of the rectangle is 188 cm.



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