The sum of the areas of the side faces of the cube is 216 cm2. find the length of the diagonal of the cube.

The cube has four side faces, then the area of one side face is:

Saa1v1v = Sside / 4 = 216/4 = 54 cm2.

Then the length of the edge of the square is √54 cm.

In a right-angled triangle ABC, according to the Pythagorean theorem, AC ^ 2 = AB ^ 2 + BC ^ 2 = 54 + 54 = 108.

In a right-angled triangle ACC1, according to the Pythagorean theorem, AC1 ^ 2 = AC ^ 2 + CC1 ^ 2 = 108 + 54 = 162.

AC1 = 9 * √2 cm.

If 216 cm2 is the total surface of the cube, then AC1 = 6 * √3 cm.

Answer: The length of the diagonal of the cube is 9 * √2 cm, (6 * √3) cm.



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