The sum of the coefficients in the reaction equation feso4 + hno3 + h2so4-no + fe2 (so4) 3+ .. is equal

First, let’s equalize this reaction with the coefficients:

FeSO4 + HNO3 + H2SO4 → Fe2 (SO4) 3 + NO + H2O.

Fe = 2Fe, put 2 in front of FeSO4:

2FeSO4 + HNO3 + H2SO4 → Fe2 (SO4) 3 + NO + H2O.

3SO4 = 3SO4.

3H = 2 H, put 2 in front of HNO3 and 3 in front of H2SO4 and 4 in front of H2O:

2FeSO4 + 2HNO3 + 3H2SO4 → Fe2 (SO4) 3 + NO + 4H2O.

5SO4 = 3SO4, put 3 in front of FeSO4 and 3 in front of Fe2 (SO4) 3:

6FeSO4 + 2HNO3 + 3H2SO4 → 3Fe2 (SO4) 3 + 2NO + 4H2O.

Let’s calculate the coefficients of the equation:

6 + 2 + 3 +3 + 2 + 4 = 20.

Answer: 20.