The sum of the sides of a square and a rectangle is 48 cm. Are their areas equal if it is known that the length

The sum of the sides of a square and a rectangle is 48 cm. Are their areas equal if it is known that the length of the rectangle is 11 cm?

Since, according to the problem statement, we know the perimeter of the rectangle, we can find the sum of its two sides, for which we divide the perimeter in half:

48: 2 = 24 (cm).

Now let’s determine the width of the rectangle by subtracting its length from the result:

24 – 11 = 13 (cm).

Find the area of the rectangle:

S = 11 * 13 = 143 (cm²).

Now let’s determine the length of the side of the square, dividing its perimeter by 4:

48: 4 = 12 (cm).

Let’s calculate the area of the square:

S = 12² = 144 (cm²).

Thus, the areas of the rectangle and the square are not equal.

Answer: no, not equal.



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