The sum of the two angles of a parallelogram is 130 °. Find the smaller angle.

1. A, B, C, D – the tops of the parallelogram. ∠А + ∠С = 130 °.

2. In a parallelogram, the angles opposite each other are equal. ∠А = ∠С = 130 °: 2 = 65 °.

3. According to one of the properties of the parallelogram, the total value of the angles located on

one side is 180 °. Using it, we calculate the degree measure ∠В:

∠В = 180 ° – ∠А = 180 ° – 65 ° = 115 °.

4. ∠D is also equal to 115 °, since it is opposite to ∠В.

Answer: ∠А = ∠С = 65 ° – smaller angles of the parallelogram.



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