# The sum of the two angles of an isosceles trapezoid is 236 degrees. Find the smaller angle of the trapezoid

October 10, 2021 | education

| Let an isosceles trapezoid ABCD with bases AD and BC be given. 1. Since the bases of the trapezoid are parallel, then ∠A + ∠B = 180 °, since they are one-sided angles formed at the intersection of two parallel lines AD and BC secant AB. And since ∠B = ∠C, then ∠A + ∠C = 180 °. Thus: ∠A + ∠D = 236 °. Since ∠A = ∠D, we denote them as x: x + x = 236 °; 2 * x = 236 °; x = 236 ° / 2; x = 118 °. Then: ∠A = ∠D = x = 118 °. 1. Find the degree measure ∠B: ∠A + ∠B = 180 °; 118 ° + ∠B = 180 °; ∠B = 180 ° – 118 °; ∠B = 62 °. 1. ∠A… ∠B; 118 °> 62 °, so ∠B = ∠C is a smaller angle. Answer: ∠B = ∠C = 62 °.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.