The sum of the two angles of the parallelogram is 150 °, 136 °. Find the large angle of the parallelogram.

In a parallelogram, the opposite sides are parallel and the opposite angles are equal. Let in parallelogram ABCD the sum of two angles is 150 °.
The sum of ∠A and ∠B, ∠A and ∠D is always 180 °, since they are one-sided angles formed at the intersection of two parallel lines AD and BC secant AB.
1.a) ∠A + ∠C = 150 °.
Since ∠A = ∠C, we denote them as x:
x + x = 150 °;
2 * x = 150 °;
x = 150 ° / 2;
x = 75 °.
Then, ∠A = ∠C = x = 75 °.
b) ∠A + ∠B = 180 °;
75 ° + ∠B = 180 °;
∠B = 180 ° – 75 °;
∠B = 105 °.
∠B = ∠D = 105 °.
Answer: ∠B = ∠D = 105 °.
2.a) ∠A + ∠C = 136 °.
Since ∠A = ∠C, we denote them as x:
x + x = 136 °;
2 * x = 136 °;
x = 136 ° / 2;
x = 68 °.
Then, ∠A = ∠C = x = 68 °.
b) ∠A + ∠B = 180 °;
68 ° + ∠B = 180 °;
∠B = 180 ° – 68 °;
∠B = 112 °.
∠B = ∠D = 112 °.
Answer: ∠B = ∠D = 112 °.