The sum of the two sides of an isosceles triangle is 5 cm. Find the perimeter of the triangle if the lengths of all its sides.

The problem has several solutions.

1

Let AB = BC = 2 cm, AC = 3 cm.By condition, AB + AC = 2 + 3 = 5 cm.

Then P = 2 + 2 + 3 = 7 cm.

Let AB = BC = 4 cm, AC = 1 cm.By condition, AB + AC = 4 + 1 = 5 cm.

Then P = 4 + 4 + 1 = 9 cm.

The length of the AC cannot be equal to 4 cm, since the sum of AB + BC <AC.

2

Let A1B1 = B1C1 = 3 cm, A1C1 = 2 cm.By the condition, A1B1 + A1C1 = 3 + 2 = 5 cm.

Then P = 3 + 3 + 2 = 8 cm.

Answer: The perimeter can be 7 cm, 8 cm, 9 cm.



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