The sum of the two sides of the triangle is 68 dm, and the third side is 20 dm less than this sum.
| July 4, 2021 | education
The sum of the two sides of the triangle is 68 dm, and the third side is 20 dm less than this sum. Determine the perimeter of the triangle.
To solve this problem, you first need to determine the length of the third side of the triangle.
Since we know that it is 20 dm less than the sum of the other two sides, for this we subtract the indicated difference from 68 dm.
We get:
68 – 20 = 48 dm.
The perimeter of a triangle is the sum of all its sides.
Thus it will be:
68 + 48 = 116 dm.
Answer: The perimeter of the triangle is 116 dm.
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