The sum of the two sides of the triangle is 72dm, the third side is 18dm, less than the sum
| May 16, 2021 | education
The sum of the two sides of the triangle is 72dm, the third side is 18dm, less than the sum of its two sides, find the perimeter of the triangle.
Find the length of the third side of this triangle.
According to the condition of the problem, the sum of the two sides of this triangle is 72 dm, and the third side is 18 dm less than the sum of its two sides, therefore, the length of the third side of this triangle is 72 – 18 = 54 dm.
Find the perimeter of this triangle.
Let us denote by a and b the lengths of the sides of this triangle, the sum of which is 72 dm.
Then the perimeter of this triangle, equal to the sum of the lengths of all sides of the triangle, is:
a + b + 54 = 72 + 54 = 127 dm.
Answer: the perimeter of this triangle is 127 dm.
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