Let’s denote by x the second number from the given sequence of three consecutive even numbers.
Then the first number from this sequence will be less than the second number by 2 and will be x – 2, and the third number from this sequence will be more than the second number by 2 and will be x + 2.
From the condition of the problem it is known that the sum of these three numbers is equal to 966, therefore, we can draw up the following equation:
x – 2 + x + x + 2 = 966
We solve the resulting equation:
3x = 966;
x = 966/3;
x = 322.
Find the first, smallest number:
x – 2 = 322 – 2 = 320.
Answer: The smallest of these numbers is 320.
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