The sum of two internal criss-crossing angles at the intersection of two parallel secant lines is 150

The sum of two internal criss-crossing angles at the intersection of two parallel secant lines is 150 degrees. What are these angles equal to?

Knowing the Axiom of Parallel Lines, we know that the cross-lying angles formed at the intersection of two parallel secant lines are equal. Let’s designate the angles – x and draw up an equation according to the condition of the problem, which says that the sum of the angles x is equal to 150 degrees: x + x = 150; 2x = 150; x = 150/2; x = 75 degrees.
Answer: 75 degrees.