The sum of two opposite sides of the described quadrangle is 5 dm. Find the perimeter of this quadrilateral

Since a circle is inscribed in a quadrilateral ABCD, by the property of such a quadrangle, the sums of the lengths of the opposite sides of the quadrilateral are equal.

AD + BC = AB + CD.

By condition, AB + CD = 5 dm, then AD + BC = 5 dm.

The perimeter of the quadrilateral is: Ravsd = (AB + CD) + (AD + BC) = 5 + 5 = 10 dm.

Answer: The perimeter of the quadrangle is 10 dm.

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