The surface area of the parallelepiped is 27. What is the surface area of the parallelepiped
| September 5, 2021 | education
The surface area of the parallelepiped is 27. What is the surface area of the parallelepiped if each of its edges is reduced by three times?
The surface area of the parallelepiped is:
S = 2 • (ab + bc + ca) = 27
And if each of its edges is reduced by a factor of 27, the area becomes equal to:
2 • ((fractions) a / 3 • b / 3 + a / 3 • c / 3 + b / 3 • c / 3) = 1/9 • 2 • (ab + bc + ca) = 1/9 • 27 = 3
Then the surface area of the parallelepiped will be equal to 3
Answer: 3
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