The swimmer swam the swimming pool 50 m long two times – back and forth.

The swimmer swam the swimming pool 50 m long two times – back and forth. Find the path and module of movement of the swimmer.

Given:
H = 50 meters – the length of the pool;
n = 2 times – the swimmer swam back and forth 2 times.
It is required to determine the swimmer’s path S (meter) and the module of his movement L (meter).
According to the condition of the problem, the swimmer swam the pool back and forth 2 times. In one swim, a swimmer covers a path equal to:
S1 = 2 * H.
In n heats, the swimmer will swim a path equal to:
S = S1 * n = 2 * H * n = 2 * 50 * 2 = 4 * 50 = 200 meters.
Let the swimmer start swimming from some point X0. Having swum there and back 2 times, he again returned to the same point. Therefore, the module of its movement will be equal to zero (L = 0).
Answer: the distance traveled is 200 meters, the movement is zero.