The takeoff roll is 1215 m, and the takeoff speed is 270 km / h. Find the takeoff time of the plane.

Given: S (takeoff run length, distance traveled) = 1215 m; V (the speed of the considered aircraft at the moment of separation from the ground) = 270 km / h (in the SI system V = 75 m / s).

The take-off time of the considered aircraft is expressed from the formula: S = (V + V0) * t / 2 = (V + 0) * t / 2, whence t = 2S / V.

Let’s make a calculation: t = 2 * 1215/75 = 2430/75 = 32.4 s.

Answer: The take-off time of the aircraft in question is 32.4 s.



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