The tangent of the acute angle of rectangular trapezium is 0.4. Incidentally, its greater base, if a smaller base is equal to height and equal to 14.
ABCD – rectangular trapezium
Angle B = Angle A = 90
CK = AB = BC = 14
TG <D = 0.4
Ad = ak + kd;
AK = 14.
We find KD from the triangle CKD.
The triangle CKD is rectangular (angle K = 90).
Tangent angle is the attitude of the opposite category to the tangent cathet.
TG <D = CK / KD
KD = CK / TG <d = 14 / 0.4 = 35.
Ad = ak + kd = 14 + 35 = 49.
Answer: ad = 49.
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