The tangent of the acute angle of rectangular trapezium is 0.4. Incidentally, its greater base

The tangent of the acute angle of rectangular trapezium is 0.4. Incidentally, its greater base, if a smaller base is equal to height and equal to 14.

Given:
ABCD – rectangular trapezium
Angle B = Angle A = 90
CK = AB = BC = 14
TG <D = 0.4
Find: AD-?
Decision:
Ad = ak + kd;
AK = 14.
We find KD from the triangle CKD.
The triangle CKD is rectangular (angle K = 90).
Tangent angle is the attitude of the opposite category to the tangent cathet.
TG <D = CK / KD
KD = CK / TG <d = 14 / 0.4 = 35.
Ad = ak + kd = 14 + 35 = 49.
Answer: ad = 49.