The tank contains 30 kg of water at 20 degrees. It was brought to a boil and evaporated 5 kg.

The tank contains 30 kg of water at 20 degrees. It was brought to a boil and evaporated 5 kg. How much heat did you spend on this?

According to the formula for the amount of heat for vaporization: Q = m * L;

m is the mass of water for vaporization;

L – specific heat of vaporization of water at 100 degrees (found from the table)

Answer: The amount of heat required for 5 kg of water vaporization is 21.6 multiplied by 10 to the 4th power



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