# The tank is in the shape of a parallelepiped 1.5 m long, 50 cm wide and 80 cm high, filled with gasoline.

**The tank is in the shape of a parallelepiped 1.5 m long, 50 cm wide and 80 cm high, filled with gasoline. Determine the pressure and pressure of the gasoline on the bottom of the tank.**

Let the length of the tank L = 1.5 m, its width a = 50 cm = 0.5 m, the height of the tank h = 80 cm = 0.8 m.

The pressure of the liquid (gasoline) is found by the formula:

p = ρ * g * h, where ρ = 710 kg / m ^ 3 is the density of gasoline.

Let’s calculate the pressure of gasoline at the bottom of the tank of a known height:

p = 710 * 10 * 0.8 = 5680 Pa.

We express the pressure force from the formula:

p = F / S, where S is the area of the base of the parallelepiped and S = L * a. Then:

F = p * S = p * L * a = 5680 Pa * 1.5 m * 0.5 m = 4260 N.

Answer: p = 5680 Pa, F = 4260 N.