The tavern covered 1.2 km in the first 10 minutes. What path will he cover in 0.5 hours, moving at the same speed.

Task data: t1 (initial tractor travel time) = 10 min (1/6 h); S1 (initial distance traveled) = 1.2 km; t2 (considered travel time) = 0.5 h; the speed of this tractor is constant.

The path that a given tractor will have time to pass can be expressed from the equality: S1 / t1 = V (tractor speed) = S2 * t2, whence S2 = S1 * t2 / t1.

Let’s calculate: S2 = 1.2 * 0.5 / 1/6 = 1.2 * 0.5 * 6 = 3.6 km.

Answer: In 0.5 hours, this tractor will have time to cover the distance of 3.6 km.




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