The temperature of a 1 kg piece of lead is 37 ° C. How much heat must be transferred

| June 19, 2021 | education

The temperature of a 1 kg piece of lead is 37 ° C. How much heat must be transferred to this piece to melt half of its mass? The melting point of lead is 327 ° C.

To find the heat transferred to the considered piece of lead to melt half of its mass, we use the formula: Q = Cc * m * (tmelt – t) + λ * m / 2.

Constants and variables: Сс – specific heat capacity of lead (Сс = 140 J / (kg * K)); m is the mass of the piece (m = 1 kg); tmelt – melting point (according to the condition t = 327 ºС); t – initial temperature (t = 37 ºС); λ – specific heat of fusion (λ = 0.25 * 10 ^ 5 J / kg).

Calculation: Q = Cc * m * (tmelt – t) + λ * m / 2 = 140 * 1 * (327 – 37) + 0.25 * 10 ^ 5 * 1/2 = 53.1 * 10 ^ 3 J = 53.1 kJ.

Answer: The considered piece of lead should receive 53.1 kJ of heat.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.